Br2 + 2nai → 2nabr + i2
WebNov 21, 2024 · D. 2NaI + Br2 →2 NaBr + I2 reacción de desplazamiento, porque el ioduro de sodio al reaccionar con el bromo, el bromo sustituye al iodo y el iodo queda solo . E. SO3 + H2O →H2SO4 reacción de composición o síntesis, porque dos sustancias el anhídrido sulfúrico y el agua se unen para formar el ácido sulfúrico. Publicidad Nuevas preguntas … Webd. 2NaI + Br2 → 2NaBr + I2 e. Cu (NO3)2 + Zn → Zn (NO3)2 + Cu Answer) Option C c. 2NaCl + Pb (NO3)2 → PbCl2 + 3NaNO3 1 Attachment docx Related Answered Questions Explore recently answered questions from the same subject Answered over 90d ago
Br2 + 2nai → 2nabr + i2
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WebScience Chemistry Given the following reaction: Br2 + 2NaI → I2 + 2NaBr How many grams of sodium bromide (NaBr) will be produced from 2.25 g of bromide (Br2), assuming sodium iodide (NaI) is available in excess? b) You did the reaction from question 53 and got a mass of 1.82 g of sodium bromide (NaBr). What is the percent yield for this experiment? WebNov 12, 2024 · Br2 (l) + 2NaI (aq) → I2 (s) + 2NaBr (aq) A) Bromine (Br) is oxidized, and iodine (I) is reduced. B) Iodine (I) is oxidized, and bromine (Br) is reduced. C) Sodium (Na) is oxidized, and bromine (Br) is reduced. D) Bromine (Br) is oxidized, and sodium (Na) is reduced. did you get it? so nobody got the answers still Advertisement jaussuhiiii Answer:
WebDec 24, 2024 · For NaF (aq)+Br2 (aq) If the reaction is possible, the balanced equation would be: 2NaF (aq) + Br2 (aq) -> F2 (g) + 2NaBr (aq) F- is the reducing agent in reactants which forms F2, the oxidizing agent in the products. Br2 is the oxidizing agent in the reactants which forms Br-, the reducing agent in the products. F- < Br- reducing agent … WebTrong bài viết này thptninhchau.edu.vn sẽ chia sẻ chuyên sâu kiến thức của hoa hoc 10 ket noi tri thuc bai 21 nhom halogen dành cho bạn
WebAnswered: Br2 (l) + 2NaI (aq) → I2 (s) + 2NaBr (aq)… bartleby. Homework help starts here! Science Chemistry Br2 (l) + 2NaI (aq) → I2 (s) + 2NaBr (aq) Which elements are … WebJun 23, 2024 · Cho các phản ứng sau: (a) Cl2 + 2NaBr (dd) → 2NaCl + Br2 (b) Br2 + 2NaI (dd) → 2NaBr + I2 (c) F2 + 2NaCl (dd) → 2NaF + Cl2 (d) Cl2 + 2NaF (dd) → 2NaCl + F2 (e) HF + AgNO3 (dd) → AgF + HNO3 (f) HCl + AgNO3 (dd) → AgCl + HNO3 Số phương trình hóa học viết đúng là A. 4. B. 5. C. 2. D. 3. Neo Pentan chọn trả lời 23.06.2024 Bình luận …
Web2NaI (aq)+Br2 (l)→2NaBr (aq)+I2 (s) What is the net ionic equation? And how is this awnser incorrect? 2Br (l)+2I^- (aq)→2Br^- (aq)+2I (s) This problem has been solved! You'll get a detailed solution from a subject matter expert that …
Webbr2与nai溶液反应离子方程式-br2Br2+2NaI→2NaBr+I2左侧：Br2：2-；NaI：1+右侧：NaBr：1+；I2：wk.baidu.com- 首页 文档 视频 音频 文集 文档 saint belle clothingWebBalance the equation Br2 + NaI = NaBr + I2 using the algebraic method or linear algebra with steps. Label Each Compound With a Variable Label each compound (reactant or … thiesens cedar rapids iowa neWebCalculate the net ionic equation for I2 (s) + 2NaBr (aq) = 2NaI (aq) + Br2 (l). Redox (Oxidation-Reduction) Reaction I2 + NaBr = NaI + Br2 might be a redox reaction. … thiesens in dewitt iaWebNov 22, 2024 · Cl2(g) + 2NaBr(aq) ===> 2NaCl(aq) + Br2(g) Chlorine (Cl) on the left goes from oxidation number of zero, to oxidation number of 1- on the right. It has thus been reduced. Br on the left goes from oxidation number of 1- to zero on the right. It has thus been oxidized. Answer is D. Br– in NaBr is oxidized; Cl 2 is reduced. saint bede the venerable churchWeb已知下列反应可以发生:Br2 + 2NaI = 2 NaBr + I2. Cl2+ 2NaBr = 2NaCl + Br2.则关于Cl2, Br2 ,I2氧化性强弱说法中.正确的是A．氧化性: I2>Br2 >Cl2B．氧化性: Br2 >I2>Cl2C．氧化性: Cl2 > Br2 > I2D．氧化性: I2>Cl2 >Br2 ... 由反应：①Tl 3+ ＋2Ag→Tl ＋ ＋2Ag + ；②Fe＋Cu 2+ →Fe 2 ... thiesens online auctionWebJan 1, 2024 · 高中化学必修二期中复习资料高中化学必修二全册复习资料 第一章物质结构元素周期律 第一节 元素周期表 一元素周期表的结构 周期序数核外电子层数 主族序数最外层电子数 原子序数核电荷数质子数核外电子数 短周期第123周期 周期:7个共七个横行 thiesens heatersWeb7．现对卤素单质Cl2，Br2，I2 ... 振荡后加入少量四氯化碳，振荡、静置上层为浅黄色（或无色）下层为紫红色化学方程式：Br2+2NaI=I2+2NaBr结论：（1）卤素单 … saint benedict abbey